m ( CaO ) = M ( CaO ) ⋅ n ( CaO ) = 56 ,1 g ⋅ mol − 1 ⋅ 0,554 mol ≈ 31 ,08 g m ( H 2 O ) = M ( H 2 O ) ⋅ n ( H 2 O ) = 18 ,0 g ⋅ mol − 1 0,554 mol ≈ 9 ,97 g nitalic { m(CaO) = M(CaO) cdot n(CaO) = 56,1g cdot mol^-1 cdot 0,554mol approx 31,08g } newline nitalic { m(H_2 O) = M(H_2 O) cdot n (H_2 O) = 18,0g cdot mol^-1 0,554 mol approx 9,97g }